Respuesta :

Step-by-step explanation:

in isos.Δ PQR


∠QPS = ∠QRS = 47° (ISOS. Δ PROP.)

∴, in Δ PQS and Δ SQR,

  ∠QPS = ∠QRS

       PQ = RQ

  ∠PQS = ∠RQS

∴, Δ PQS ≅ Δ RQS (SAS CONGRUENCE)

∴, PS = SR = 17 (CPCT).