Answer:
The correct option is B.
Step-by-step explanation:
According to the Pythagoras theorem, in a right angled triangle the sum of squares of both legs is equal to the square of hypotenuse.
[tex]hypotenuse^2=perpendicular^2+base^2[/tex]
From the given triangle it is clear that the measure of both legs are 6 units and √(63) units , and the measure of hypotenuse is 10 units.
[tex](10)^2=(\sqrt{63})^2+(6)^2[/tex]
Solve the LHS,
[tex]LHS=(10)^2[/tex]
[tex]LHS=100[/tex]
Solve the RHS,
[tex]RHS=(\sqrt{63})^2+(6)^2[/tex]
[tex]RHS=63+36[/tex]
[tex]RHS=99[/tex]
[tex]LHS\neq RHS[/tex]
The given triangle FGH is not a right angled triangle, therefore the correct option is B.
