Respuesta :
Answer: 1.274 N minimum force required to slide the book across the surface
Explanation:
Mass of the book = m = 0.2 kg
Normal force acting on the book,N = mg
Coefficient of friction =[tex]mu_s[/tex] = 0.65
Minimum force required to slide the book across the surface= F
[tex]F=\mu_s\times N[/tex]
[tex]F=0.65\times 0.2 kg\times 9.8 m/s^2=1.274 N[/tex]
1.274 N minimum force required to slide the book across the surface
Answer : F = 1.274 N
Explanation :
It is given that,
Coefficient of static friction, [tex]\mu_s=0.65[/tex]
Mass of the book, [tex]m=0.2\ kg[/tex]
We know that the relation between static friction and the force is :
[tex]F=\mu_s\times N[/tex]
Where N is the normal force (N = mg)
So, [tex]F=\mu_s\times m\times g[/tex]
[tex]F=0.65\times 0.2\ kg\times 9.8\ m/s^2[/tex]
[tex]F=1.274\ N[/tex]
Hence, the minimum initial applied force is required to slide the books across the surface is 1.274 N.
