Answer: 72 grams of water will be produced.
Explanation:
To calculate the number of moles, we use the formula:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ....(1)
Mass of propane = 44 grams
Molar mass of propane = 44 grams
Putting values in above equation, we get:
[tex]\text{moles of propane}=\frac{44g}{44g/mol}=1mole[/tex]
For the reaction of combustion reaction of propane, the equation follows:
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
By Stoichiometry of the reaction,
1 mole of propane produces 4 moles of water.
So, 1 mole of propane will produce = [tex]\frac{1}{1}\times 4=4moles[/tex] of water.
Now, to calculate the amount of water, we use equation 1, we get:
Molar mass of water = 18 g/mol
[tex]4mol=\frac{\text{Mass of water}}{18g/mol}[/tex]
Mass of water produced = 72 grams
Hence, 72 grams of water will be produced.
