Answer:
see explanation
Step-by-step explanation:
Express the left side as a single fraction with abc as the common denominator
[tex]\frac{a^2}{bc}[/tex] + [tex]\frac{b^2}{ca}[/tex] + [tex]\frac{c^2}{ab}[/tex]
= [tex]\frac{a^3+b^3+c^3}{abc}[/tex]
[ a³ + b³ + c³ = (a + b + c)(a² + b² + c² - ab - bc - ac ) + 3abc ]
since a + b + c = 0 then
(a + b + c)(a² + b² + c² - ab - bc - ac) = 0 , hence
a³ + b³ + c³ = 3abc
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= [tex]\frac{3abc}{abc}[/tex] = 3
