Answer: A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.
Step-by-step explanation:
Since we have given that
Radius of inner circle = 57 ft
As we know the formula for "Circumference of circle":
[tex]Distance=Circumference=2\pi r\\\\Distance=2\times \frac{22}{7}\times 57\\\\Distance=358.28\ Ft[/tex]
Since we have also mentioned that there is 2 feet wide circular track for a camera dolly.
So, Radius of outer circle will be given as
[tex]57+2\\=59\ ft[/tex]
So, Distance = Circumference is given by
[tex]Distance=2\pi R\\\\Distance=2\times \frac{22}{7}\times 59\\\\Distance=370.85\ ft[/tex]
Hence, Difference between the outer rail travel than a wheel on the inner rail travel is given by
[tex]370.85-358.28\\\\=12.57\ ft[/tex]
Therefore, A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.
