Answer:
The bi-conditional is false.
Step-by-step explanation:
We are told:
1. If a number is divisible by 6 then it is divisible by three, AND
2. If a number is divisible by 3 then it it divisible by six.
Both conditions must be true for the original bi-conditional statement to be true.
Statement 2 can easily be disproved by the counter example:
15 is divisible by 3 but is not divisible by six.
Which is why the given bi-conditional is FALSE.
Answer:
It is false because at least one part of the biconditional is false.
Step-by-step explanation:
