Answer:
The equation which describe this function is 5x + 11y = 37
Step-by-step explanation:
To find the slope
slope = (y₂ - y₁)/(x₂ - x₁)
slope = (13 - 2)/(-2 - 3) = 11/-5
To find the equation
(x - 3)/(y - 2) = -11/5
5(x - 3) = -11(y - 2)
5x -15 = -11y + 22
5x + 11y = 22 + 15
5x + 11y = 37
Therefore the equation which describe this function is
5x + 11y = 37
Answer:
y = [tex]\frac{-11}{5}[/tex] x + [tex]\frac{43}{5}[/tex]
Step-by-step explanation:
Linear function is defined by y = ax+b
where a and b are constants and (x,y ) are variables given as point
using point (3,2) that is plugging x =3 and y =2 ,we
2 = 3a+b ............. equation(1)
likewise using point (-2,13) and plugging x =-2 and y =13 ,we get
13 = -2a+b .......... equation(2)
Solving the equation (1) and 2
[tex]\left \{ {{2=3a+b} \atop {13=-2a+b}} \right.[/tex]
subtracting equation 2 from equation 1
3a+b = 2
-2a+b = 13
__-_______________
we have 5a = -11
a= [tex]\frac{-11}{5}[/tex]
plugging a=[tex]\frac{-11}{5}[/tex] in equation (1),we get
3([tex]\frac{-11}{5}[/tex]) +b =2
b = 2 -3([tex]\frac{-11}{5}[/tex])
b = 2+[tex]\frac{33}{5}[/tex]
b=[tex]\frac{43}{5}[/tex]
therefore equation is obtained by plugging
a =[tex]\frac{-11}{5}[/tex] and b = [tex]\frac{43}{5}[/tex]
we get equation as
y = [tex]\frac{-11}{5}[/tex] x + [tex]\frac{43}{5}[/tex]
