You and your friend are selling tickets to a charity event. You sell 9 adult tickets and 13 student tickets for 212$. Your friend sells 4 adult tickets and 15 student tickets for $168.What is the cost of student ticket?

Respuesta :

Answer:

  $8

Step-by-step explanation:

Let a and s represent the prices of adult and student tickets, respectively. The relations described by the problem statement can be written ...

  9a +13s = 212

  4a +15s = 168

Using Cramer's method, we can find the value of s to be ...

  s = (212·4 -168·9)/(13·4 -15·9) = -664/-83 = 8

The price of a student ticket is $8.

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Comment on Cramer's method

For the equations ...

  • ax +by = c
  • dx +ey = f

the solutions can be written as ...

  • ∆ = bd-ea
  • x = (bf-ec)/∆
  • y = (cd-fa)/∆

This method is useful when the equation's coefficients don't lend themselves to "nice" arithmetic or when the value of only one variable is needed (as here).

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If you look up "Cramer's Method" in Wikipedia or other sources, you will likely find that the signs of the differences are reversed. That is, ...

  x = (ce-bf)/(ae-bd)

This makes no difference to the result of the calculation. The variable ordering shown here can be remembered as a pattern of Xs when compared to the locations of the coefficients in the given equations. Often, this permits the problem to be completely solved mentally.