Respuesta :

MrGumby

Answer:

The answers would be:

a = 1

b = -5

c = 6

Step-by-step explanation:

We can tell this because a is always equal to the coefficient of x^2. Since there is no number there, it is assumed to be 1.

b is always the coefficient of x, which in this case is -5.

c is the constant listed at the end of the equation.

carlosego

For this case, we have a quadratic function of the form:

[tex]ax ^ 2 + bx + c[/tex]

If we want to find the roots of the equation [tex]ax ^ 2 + bx + c = 0[/tex], we have:

[tex]x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}[/tex]

If we have, [tex]x ^ 2-5x + 6[/tex] then we have two coefficients given by:

[tex]a = 1\\b = -5[/tex]

And the constant term:

[tex]c = 6[/tex]

Answer:

[tex]a = 1\\b = -5\\c = 6[/tex]

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