Answer:
Resultant = 180.27 pounds
direction is 63.69 degrees
Step-by-step explanation:
We have to resolve the x and y component of both forces with respect to given angles
Fx = 150cos30 +100cos120
= 150(0.866)+100(-0.5) =129.9-50=79.9 pounds
and
Fy= 150sin30+100sin120
= 150(0.5) +100(0.866)= 75+ 86.6 =161.6 pounds
Magnitude of the resultant is = [tex]\sqrt{Fx^2+Fy^2}[/tex]
=[tex]\sqrt{(79.9)^2+(161.6)^2}[/tex]
= 180. 27 pounds
Direction of the resultant is given by arctan([tex]\frac{Fy}{Fx}[/tex]
arctan([tex]\frac{161.6}{79.9}[/tex]
=63.69 degrees
Answer:
Step-by-step explanation:
Fx = 150cos30 +100cos120
= 150(0.866)+100(-0.5) =129.9-50=79.9 pounds
and
Fy= 150sin30+100sin120
= 150(0.5) +100(0.866)= 75+ 86.6 =161.6 pounds
The magnitude of the resultant is sqrt of (Fx^2 +Fy^2) which is equal to the sqrt of (79.9)^2+(161.6)^2 = 180.27 lbs
the direction of the resultant is by the given arctan Fy/Fx =arctan 161.6/79.9= 63.69 deg
