Answer:
[tex]\frac{x^4-2x^3-3x^2-4x-8}{x-2}=(x^3-3x-8)-\frac{28}{x-2}[/tex]
Step-by-step explanation:
We are given
Dividend is
[tex]=x^4-2x^3-3x^2-4x-8[/tex]
Divisor is
[tex]=x-2[/tex]
now, we can use long division
so, we get
Quotient as
[tex]Q(x)=x^3-3x-10[/tex]
Remainder is
[tex]R=-28[/tex]
we can write as
[tex]\frac{x^4-2x^3-3x^2-4x-8}{x-2}=(x^3-3x-8)-\frac{28}{x-2}[/tex]
