Answer : The volume of gas will be, 31.26 L
Solution :
At STP, pressure of gas is 101.3 kPa and temperature of gas is 273 K.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 145 kPa
[tex]P_2[/tex] = final pressure of gas = 101.3 kPa
[tex]V_1[/tex] = initial volume of gas = 20 L
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = 250 K
[tex]T_2[/tex] = final temperature of gas = 273 K
Now put all the given values in the above equation, we get the final volume of gas.
[tex]\frac{145kPa\times 20L}{250K}=\frac{101.3kPa\times V_2}{273K}[/tex]
[tex]V_2=31.26L[/tex]
Therefore, the volume of gas will be, 31.26 L
