I need help with this last problem. Algebra 2

\sqrt[3]{x-2} +5 is your answer
Step-by-step explanation:
A horizontal translation is inside the function is inside the function. Vertical translations are outside the function. A translation to the right would be [tex]\sqrt[3]{x-2}[/tex]. After that that traslation up would be [tex]\sqrt[3]{x-2} +5[/tex]
Answer:
g(x) = (x-2) ^ 1/3 +5
Step-by-step explanation:
f(x) = x^1/3
We want to shift it 2 units to the right
h(x) = f(x+c) where c<0 to move it to the right
To move it 2 units to the right c =-2
h(x) = f(x-2)
Substitute x-2 in for x in the function
h(x) = (x-2) ^ 1/3
Now we want to shift it 5 units up
g(x) = h(x)+c where c>0 to move it up
To move it 5 units up c =5
g(x) = h(x)+5
g(x) = (x-2) ^ 1/3 +5