Answer:
2500 J
Explanation:
We can solve the problem by using the first law of thermodynamics:
[tex]\Delta U =U_f - U_i =Q-W[/tex]
where
Uf is the final internal energy of the system
Ui is the initial internal energy
Q is the heat added to the system
W is the work done by the system
In this problem, we have:
Q = +1000 J (heat that enters the system)
W = +500 J (work done by the system)
Ui = 2000 J (initial internal energy)
Using these numbers, we can re-arrange the equation to calculate the final internal energy:
[tex]U_f = U_i + Q-W=2000 J+1000 J-500 J=2500 J[/tex]
