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Hailey is roping off a rectangle around a crime scene. She used 130 feet of tape and the length is 5 feet longer than twice the width, what are the dimensions of the rectangle around the crime scene?

Respuesta :

calculista

Answer:

The dimensions of rectangle are [tex]45\ ft[/tex]  by   [tex]20\ ft[/tex]

Step-by-step explanation:

we know that

the perimeter of rectangle is equal to

[tex]P=2(L+W)[/tex]

In this problem we have

[tex]P=130\ ft[/tex]

so

[tex]130=2(L+W)[/tex]

[tex]65=(L+W)[/tex] ------> equation A

[tex]L=2W+5[/tex] -----> equation B

substitute equation B in equation A

[tex]65=(2W+5+W)[/tex]

[tex]65-5=(2W+W)[/tex]

[tex]3W=60[/tex]

[tex]W=20\ ft[/tex]

Find the value of L

[tex]L=2W+5[/tex] ------> [tex]L=2(20)+5=45\ ft[/tex]

Answer:

the answer is five times 4 like this 44444

Step-by-step explanation:

there is gonna be 4 answers u can pick there is gonna be one that is 44444 and ur gonna click that one and ur gonna put check if u have bc i am useing K12 and this is for 4th graders so the anser is gonna be 44444 and yeah i hope this help

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