Simplify completely the quantity 4 times x to the third power plus 5 times x to the 2nd power plus 3 times x all over x. (2 points) 4x2 + 5x + 3 the quantity 4 times x to the 2nd power plus 5 times x plus 3 all over x 4x2 + 5x2 + 3x 4x4 + 5x3 + 3x2
[tex]\dfrac{4x^3+5x^2+3x}{x}\\\\\\=\dfrac{x(4x^2+5x+3)}{x}\qquad \text{factored out the common term from the numerator}\\\\\\=4x^2+5x+3\qquad \text{canceled out x from numerator and denominator}[/tex]
