Respuesta :

Answer:

[tex](\frac{g}{f} )(x)=\frac{x^2-6}{3x+1}[/tex]

Step-by-step explanation:

f(x) = 3x+1

g(x)= x^2- 6

[tex](\frac{g}{f} )(x)= \frac{g(x)}{f(x)}[/tex]

Now we plug in g(x)  and f(x)

we are given with g(x) and f(x)

[tex](\frac{g}{f} )(x)= \frac{g(x)}{f(x)}=\frac{x^2-6}{3x+1}[/tex]

We cannot factor and simplify it

[tex](\frac{g}{f} )(x)=\frac{x^2-6}{3x+1}[/tex]


zainebamir540

Answer:

(g/f)(x) = x²-6 / 3x+1 , x ≠ -1/3.

Step-by-step explanation:

From question statement , we observe that

Two functions are given and we have to find their ratio.

f(x) = x+1 and g(x) = x²-6

(g/f)(x) = ?

(g/f)(x) = g(x) / f(x)

Putting the values of g(x) and f(x) to above formula,we get

(g/f)(x) = x²-6 / 3x+1

If 3x+1 = 0 ⇒ x = -1/3 then function is undefined.

Hence, (g/f)(x) = x²-6 / 3x+1 , x ≠ -1/3 which is the answer.

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