Answer:
13
Step-by-step explanation:
To fulfill an assignment by a given deadline, a team of workers had to produce 54 parts daily
let total no. of parts in assign be p n days to finish be d
54d=p
Exceeding the schedule by 6 parts per day, the team produces 54+6 = 60 parts daily
the team finished the assignment 1 day earlier n produced 18 extra parts
1 day earlier means d-1
18 extra parts means p+18
so 60(d-1)=p+18
substitute 54d=p into the eqn
60(d-1)=54d+18
60d-60=54d+18
60d-54d=18+60
6d=78
d=13
Answer:
Step-by-step explanation:
Let d be days of work by the team.
At first, a team of workers had to produce 54 parts daily:
d days × (54 parts)/day = 54d parts
Then exceeding the schedule by 6 parts per day, the team not only finished the assignment 1 day earlier, but also produced 18 extra parts:
(d-1) days × (54+6 parts)/day = 60d - 60 parts
60d-60 = 54d + 18
6d = 78
d = 13
So the answer is:
If the team is making 54 parts per day, the team works 13 days.
If the team is making 60 parts per day, the team works 12 days.
