Respuesta :
Answer:
-3x^2 -10x -16 -29/(x-2)
Step-by-step explanation:
-3x^3-4x^2+4x+3
We can do synthetic division
-3 -4 4 3
2
----------------------------
Bring the first term down
-3 -4 4 3
2
----------------------------
-3
Multiply -3 times 2
-3 -4 4 3
2 -6
----------------------------
-3
Add -4 and -6
-3 -4 4 3
2 -6
----------------------------
-3 -10
Multiply 2 *-10
-3 -4 4 3
2 -6 -20
----------------------------
-3 -10
Add 4 and -20
-3 -4 4 3
2 -6 -20
----------------------------
-3 -10 -16
Multiply the 2 by -16
-3 -4 4 3
2 -6 -20 -32
----------------------------
-3 -10 -16 -29
The result is -3x^2 -10x -16 -29/(x-2)
Answer:
(x-2)(-3x^2-10x-16) - 29
Step-by-step explanation:
test -3x^3-4x^2+4x+3 for root at x=2
-3(2)^3-4(2)^2+4(2)+3
=-3*8-4*4+8+3
=-29
so x=2 is not a root n dividing -3x^3-4x^2+4x+3 by x-2 will have a quotient
solving by long division
-3x^3-4x^2+4x+3 x-2
-3x^2
-3x^3+6x^2
-10x^2+4x+3
-10x
-10x^2+20x
-16x+3
-16
-16x+32
-29
so divide -3x^3-4x^2+4x+3 by x-2
= (x-2)(-3x^2-10x-16) - 29
