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Elwin is standing 50.0m from a large bell. He throws a rock at the bell and hears the sound of the bell 4.50s later. If the speed of sound is 330m/s, what was the speed of the rock?

Respuesta :

Time taken by the sound to come from bell to Elwin

[tex]t = \frac{d}{v}[/tex]

here we know that

d = 50 m

v = 330 m/s

now from above equation we have

[tex]t_1 = \frac{50}{330} = 0.15 s[/tex]

now since we know that total time taken to hear the sound is 4.50s

so here we will have time to reach the rock to the bell is

[tex]t_2 = t - t_1[/tex]

[tex]t_2 = 4.50 - 0.15 = 4.35 s[/tex]

now we know that distance of the bell is 50 m

so speed of the rock is given as

[tex]v = \frac{d}{t_2} = \frac{50}{4.35}[/tex]

[tex]v = 11.5 m/s[/tex]

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