Respuesta :
Answer:
2n+7)(2n+7)
Step-by-step explanation:
We are given an expression 4n² + 28n + 49 and we have to factorize it
4n² + 28n + 49
We can write 4n² as (2n)²
We can write 49 as 7²
We can also write 28n as 2×7×2n
so rewriting the above expression
(2n)² + 2×7×2n + 7²
Apply perfect square formula: [tex](a+b)^2=a^2+2ab+b^2[/tex]
a = 2n ; b = 7
the expression become
(2n+7)²
It can also be written as (2n+7)(2n+7)
Answer:
(2n+7)²
Step-by-step explanation:
Given expression is
4n²+28n+49
(a+b)² = a²+2ab+b² is formula to find factors of any quadratic expression
4n² is square of 2n.
49 is square of 7.
And 28n is 2(2n)(7).
a = 2n and b = 7
Hence, we can put above value in formula.
(2n+7)² = ( (2n)²+2(2n)(7) + (7)² )
(2n+7)² = ( 4n² + 28n +49)
Hence, (2n+7)² are factors of 4n²+28n+49.