Answer:
Given the system of equation:
[tex]3x-y=12[/tex] .....[1]
[tex]-3x+5y= -4[/tex] .....[2]
Adding equation [1] and [2] to eliminate x we have;
[tex](3x-y)+(-3x+5y) = 12-4[/tex]
[tex]3x-y-3x+5y= 8[/tex]
Combine like terms;
[tex]4y= 8[/tex]
Divide both sides by 4 we get;
y = 2
Substitute the value of y in [1] we get;
3x-2= 12
Add 2 to both sides we get;
3x = 14
Divide both sides by 3 we get;
x = 4.67
Therefore, the solution for this system of equation is, (4.67, 2)
