Respuesta :
Answer:
23.5
Step-by-step explanation:
substitute x = 4 and y = 5 into the expression
= [tex]\frac{4^2+5^3}{2+4}[/tex]
= [tex]\frac{16+125}{6}[/tex] = [tex]\frac{141}{6}[/tex] = 23.5
The value of the given expression [tex]\frac{x^2+y^3}{2+x}[/tex] for x=4 and y=5 is 23.5. So, option D) 23.5 is correct. This is calculated by substituting the x and y values in the expression.
Given expression:
It is given that the expression is a fraction with x squared plus y cubed in the numerator and 2 plus x in the denominator is written as [tex]\frac{x^2+y^3}{2+x}[/tex].
It is given that the values of x and y are x=4 and y=5
Evaluating the expression:
On substituting the values x=4 and y=5 in the given expression we get,
= [tex]\frac{(4)^2+(5)^3}{2+4}[/tex]
= [tex]\frac{16+125}{6}[/tex]
= [tex]\frac{141}{6}[/tex]
= 23.5
Therefore, the value of the given expression is 23.5 for x=4 and y=5.
Learn more about such evaluating expression problems here:
https://brainly.com/question/11388301
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