Respuesta :
Answer:
t = (t₁ · vr)/ (vj - vr) = 45 seconds
Step-by-step explanation:
Given:
Initial time from Ricardo t₁ = 15 seconds, Ricardo's velocity (speed) vr = 3 ft/s,
John's velocity (speed) vj = 4 ft/s
Requested time when John catch Ricardo t = ?
During 15 seconds, Ricardo moved away
S = vr · t₁ = 3 ft/s · 15 s = 45 feet.
From that moment, the same time runs for both of them
Ricardo's path is S₁ = vr · t and John's path is S₂ = vj · t
S + S₁ = S₂ => S = S₂ - S₁ => 45 = vj · t - vr · t
When we draw t we get:
t ( vj - vr) = 45 t = 45 / (vj - vr) = 45 / (4 - 3) = 45 / 1 = 45 seconds
t = 45 seconds
S₁ = vr · t = 3 · 45 = 135 ft
S₂ = vj · t = 4 · 45 = 180 ft
God with you!!!
The equation that shows how long it will take John to catch up with Ricardo is 3t + 45 = 4t
Linear equations involving rate
Rate at which Ricardo swims = 3 feet per second
Rate at which John swims = 4 feet per second
Ricardo starts 15 seconds before John
Let the time taken for John to catch up with Ricardo be t
Time spent by Ricardo = t + 15
Distance = Speed x Time
Distance covered by Ricardo = 3 x (t + 15)
Distance covered by Ricardo = 3t + 45
Distance covered by John = 4t
Distance covered by Ricardo = Distance covered by John
3t + 45 = 4t
Therefore, the equation that shows how long it will take John to catch up with Ricardo is 3t + 45 = 4t
Learn more on linear equations here: https://brainly.com/question/2030026
