Respuesta :
Answer:
2140 m^3 approximately.
Step-by-step explanation:
The volume of a cone is 1/3 π r^2 h
Here r = 15 and h = 9.1
so the vulume is about 1/3 * 3.14 * 15^2 * 9.1
= 2140 m^3 approximately.
Answer:
Volume(V) of the cone is given by:
[tex]V = \frac{1}{3} \pi r^2h[/tex]
where,
r is the radius of the cone and h is the height of the cone.
As per the statement:
A cone-shaped pile of gravel has a diameter of 30 m and a height of 9.1 m.
⇒diameter(d) = 30 m and h = 9.1 m
Diameter(d) is given by:
[tex]d = 2r[/tex]
then;
[tex]30 = 2r[/tex]
Divide both sides by 2 we have;
15 = r
or
r = 15 m
Substitute the given values and use [tex]\pi = 3.14[/tex] we have;
[tex]V = \frac{1}{3} \cdot 3.14 \cdot 15^2 \cdot 9.1[/tex]
[tex]V = \frac{1}{3} \cdot 3.14 \cdot 225 \cdot 9.1[/tex]
Simplify:
V = 2143.05 cubic meter.
Therefore, the best approximate the volume of the pile of gravel is, [tex]2143.1 m^3[/tex]
