Answer: The amount of heat required is 5 Calories.
Explanation:
To calculate the amount of heat absorbed, we use the equation:
[tex]q=m\times C_p,s\times \Delta T[/tex]
where,
q = amount of heat absorbed = ?
m = mass of ice = 100 g
[tex]C_{p,s}[/tex] = specific heat capacity of ice = [tex]0.5Cal/g^oC[/tex]
[tex]\Delta T[/tex] = change in temperature = [tex]1^oC[/tex]
Putting all the values in above equation, we get:
[tex]q=10g\times 0.5Cal/g^oC\times 1^oC=5Cal[/tex]
Hence, the amount of heat required is 5 Calories.
