What is the degree of (f*g)(x)?

Answer: 6
Step-by-step explanation:
Degree of a function is the highest power of the variable present in a monomial.
Here, The given functions are,
[tex]f(x) = 3x^2[/tex]
And, [tex]g(x) = 4x^3+1[/tex]
Thus, [tex](fog)(x) = f[g(x)] = f[4x^3+1] = 3(4x^3+1)^2 = 3(16x^6+1+8x^3)[/tex]
Since, In the function fog the highest power of x is 6.
⇒ The degree of (fog)(x) is 6.
Answer:
Degree of fog(x) is 6
Step-by-step explanation:
Degree of the function is highest exponent of the variable .
In order to find that we shall find the composition of the function as follows :
fog(x) is given by f(g(x))
And here f(x) =[tex]3x^2[/tex]
f(g(x)) will be [tex]3(g(x))^2[/tex]
and then plugging the value of g(x) =[tex]4x^3+1[/tex]
so fog(x) = f(g(x)) = [tex]3(4x^3+1)^2[/tex]
= [tex]3(4x^3+1)^2=3(16x^6+1+8x^3)\\[/tex]
Here highest exponent of the function is 6
therefore degree of ( fog)(x) is 6.