Respuesta :

Answer: Our required function becomes

[tex]\frac{f(x)}{g(x)}=\frac{3x+1}{x^2-6}\\\\x\neq \pm\sqrt{6}[/tex]

Step-by-step explanation:

Since we have given that

[tex]f(x)=3x+1\\\\g(x)=x^2-6[/tex]

We need to write in quotient form i.e. [tex]\frac{f(x)}{g(x)}[/tex]

So, our function becomes,

[tex]\frac{f(x)}{g(x)}=\frac{3x+1}{x^2-6}\\\\x\neq \pm\sqrt{6}[/tex]

Hence, our required function becomes

[tex]\frac{f(x)}{g(x)}=\frac{3x+1}{x^2-6}\\\\x\neq \pm\sqrt{6}[/tex]


zainebamir540

Answer:

Choice B is correct answer.

Step-by-step explanation:

From question statement, we observe that

Two binomial functions are given and we have to find quotient function.

f(x) = 3x+1 and g(x) = x²-6

(f/g)(x) = ?

(f/g)(x) = 3x+1 / x²-6

If x²-6 = 0 ⇒ x = ±√6 , then (f/g)(x)  is not defined.

hence, solution is 3x+1 / x²-6 , x ≠ ±√6.


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