Answer :
Acceleration of the cat is [tex]a=5\ m/s^2[/tex]
Explanation:
It is given that,
Initial speed of the cat, u =0 (at rest)
Final speed of the cat, v = 10
Time taken, t = 2 s
Let a is the acceleration of the car. We know that the rate of change of velocity of an object is called its acceleration. Mathematically, it is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{10-0}{2}[/tex]
[tex]a=5\ m/s^2[/tex]
So, the acceleration of the cat was [tex]5\ m/s^2[/tex]. Hence, this is the required solution.
The acceleration of the cat to reach its maximum velocity of 10 m/s in 2 seconds is 5m/s².
We know that according to the first equation of motion,
[tex]v-u=at[/tex]
Given to us
Time is taken by the cat to reach the final velocity = 2 seconds
Final velocity of the cat = 10 m/s
The initial velocity of the cat = 0 m*/s
Substitute the values in the equation,
[tex]v-u=at\\\\10-0 = a(2)\\\\a = 5\ m/s^2[/tex]
Hence, the acceleration of the cat to reach its maximum velocity of 10 m/s in 2 seconds is 5m/s².
Learn more about Equation of motion:
https://brainly.com/question/5955789
