Answer: The temperature will be 1501.47 K.
Explanation:
To calculate the temperature of the gas when pressure is increased, we use the equation given by Gay-Lussac's Law.
This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
Mathematically,
[tex]P\propto T[/tex]
or,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are the initial pressure and initial temperature of the gas.
[tex]P_2\text{ and }T_2[/tex] are the final pressure and final temperature of the gas.
We are given:
[tex]P_1=101.5kPa\\T_1=300K\\P_2=508kPa\\T_2=?K[/tex]
Putting values in above equation, we get:
[tex]\frac{101.5kPa}{300K}=\frac{508kPa}{T_2}\\\\T_2=1501.47K[/tex]
Hence, the temperature will be 1501.47 K
