Determine the intercepts of the line. 8x-5y=-11

The intercepts are the where the line or graph crosses that axis. So, the value of 'x' when the graph crosses the y-axis is '0' and the value of 'y' when the graph crosses the x-axis is '0'. In an equation, you can find the intercepts by plugging in '0' for the other variable and solving:

x-intercept = 8x - 5(0) = -11 or 8x = -11 or x = [tex]\frac{-11}{8}[/tex]

y-intercept = 8(0) -5y = -11 or -5y = -11 or y = [tex]\frac{11}{5}[/tex]

bhoopendrasisodiya34 bhoopendrasisodiya34 · Answer 2 · 2022-07-21T15:47:56+02:00

x-intercept(s) is (-11/8, 0) and y-intercept(s) is (0, 11/5).

We need to find the intercepts of the line 8x-5y=-11.

How to find intercepts of the line?

To find the x-intercept, substitute 0 for y and solve for x. To find the y-intercept, substitute in 0 and x and solve for y.

Now, put y=0 in 8x-5y=-11, we get 8x=-11

⇒x=-11/8

x-intercept(s):(-11/8, 0)

Now, put x=0 in 8x-5y=-11, we get -5y=-11.

⇒x=11/5

y-intercept(s):(0, 11/5)

Therefore, x-intercept(s) is (-11/8, 0) and y-intercept(s) is (0, 11/5).

To learn more about intercepts visit:

https://brainly.com/question/14180189.

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