Answer:
See explanation
Step-by-step explanation:
Adding fractions with different denominators, Mark needs to convert both fractions in equivalent fractions with the same denominators. Since the LCD is 3x, then Mark has to rewrite the second fraction as fraction with denominator 3x:
[tex]\dfrac{x-4}{x}=\dfrac{3(x-4)}{3x}.[/tex]
Now
[tex]\dfrac{7x}{3x}+\dfrac{x-4}{x}=\dfrac{7x}{3x}+\dfrac{3(x-4)}{3x}=\dfrac{7x+3(x-4)}{3x}=\dfrac{7x+3x-12}{3x}=\dfrac{10x-12}{3x}.[/tex]
