For this case we want to know the difference of:
[tex]\frac {x-8} {3x} - \frac {3x} {x ^ 2} =[/tex]
We cross multiply:
[tex]\frac {x ^ 2 (x-8) -9x ^ 2} {3x ^ 3} =[/tex]
We solve the operation of parentheses:
[tex]\frac {x ^ 3-8x ^ 2-9x ^ 2} {3x ^ 3} =[/tex]
We combine similar terms, taking into account that equal signs are added and the same sign is placed:
[tex]\frac {x ^ 3-17x ^ 2} {3x ^ 3} =[/tex]
We simplify:
[tex]\frac {1} {3} - \frac {17} {3x}[/tex]
Answer:
[tex]\frac {1} {3} - \frac {17} {3x}[/tex]
