Answer:
71.4 cm³
Step-by-step explanation:
Density = mass/volume
D = m/V Multiply each side by V
DV = m Divide each side by D
V = m/D
Data:
m = 90.0 g
D = 1.26 g/cm³
Calculation:
V = 90.0 g × (1 cm³/1.26 g)
= 71.4 cm³
The student should measure out 71.4 cm³ of glycerol.
A chemistry student needs 90.0g of glycerol for an experiment. By consulting the CRC handbook of chemistry and physics, the student discovers that the density of glycerol is 1.26 g/cm³. The volume of glycerol the student should pour out is 71.42 cm³.
To find the volume use the expression
Volume = [tex]\frac{\text{Mass}}{\text{Density}}[/tex]
Volume = [tex]\frac{90.0\ g}{1.26 g/cm^3}[/tex]
Volume = 71.42 cm³
Thus, from the above conclusion we can say that A chemistry student needs 90.0g of glycerol for an experiment. By consulting the CRC handbook of chemistry and physics, the student discovers that the density of glycerol is 1.26 g/cm³. The volume of glycerol the student should pour out is 71.42 cm³.
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