Answer: (C) bottom left graph
Step-by-step explanation:
Create a table for each interval:
[tex]\begin {array}{c|l}\underline{\ x\ }&\underline{(x+2)^2=y}\\ -3&(-3+2)^2=1\\-2&(-2+2)^2=0\\-1&(-1+2)^2=1\quad \text{ope n dot}}\\\end{array}\\\\\text{Note: All of the graphs satisfy these coordinates}\\\\\begin {array}{c|l}\underline{\ x\ }&\underline{(|x|+1=y}\\ -1&|-1|+1=2\quad \text{closed dot}}\\0&|0|+1=1\\1&|1|+1=2\quad \text{closed dot}}\\\end{array}\\\\\text{Note: Graph C is the only graph that satisfies these coordinates}[/tex]
No need to create the table for the last interval.
