Answer:
The smallest zero is [tex]x=-3[/tex]
Step-by-step explanation:
The given function is
[tex]h(x)=4x^2-8x-60[/tex]
To find the zeros of this function, we equate it to zero.
[tex]\Rightarrow 4x^2-8x-60=0[/tex]
Dividing through by 4 gives
[tex]x^2-2x-15=0[/tex]
We split the middle term to get;
[tex]x^2-5x+3x-15=0[/tex]
Factor
[tex]x(x-5)+3(x-5)=0[/tex]
Factor further to get;
[tex](x-5)(x+3)=0[/tex]
[tex](x-5)=0,(x+3)=0[/tex]
The zeros are
[tex]x=5,x=-3[/tex]
The smallest zero is
[tex]x=-3[/tex]
