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A swimmer bounces almost straight up from a diving board and falls vertically feet first into a pool. She starts with a speed of 4.8m/s, and her takeoff point is 1.95m above the pools surface. For how long are her feet in the air, in seconds?

Respuesta :

s = V0 t + 1/2 g t^2     distance formula

-1.95 = 4.8 t - 1/2 * 9.8 * t^2      positive direction is up

4.9 t^2 - 4.8 t -1.95 = 0

Solving the quadratic for t gives 1.29 sec


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