Answer:
Step-by-step explanation:
Givens
DTBC is a rhombus
<RTB = <FCB
Find
RD = DF
Solution
- <RTB = <FCB Given
- TD = DC Property of a Rhombus (all four sides are equal)
- <RDT = <FDC Vertically opposite angles are equal
- ΔRDT ≅ ΔFDC Δ = triangle. The Δs are congruent by ASA.
- RD = DF Parts of congruent triangles are congruent.
You will get problems like the way you were trying to do it. But you should just mark out what you know. I think that you might have forgotten about vertically opposite angles.
