Hello from MrBillDoesMath!
Answer:
1. 1
2. -13/7
Discussion:
1. 2x + 4(3-2x) = 3( 2x + 2)/6 + 4 => as 3(2x+2) = 6x + 6
2x + 4(3-2x) = (6x + 6)/6 + 4 => (6x + 6)/6 = x + 1
2x + 12 - 8x = x + 1 + 4 => combine x terms on lhs
-6x + 12 = x + 5 => subtract x from both sides
-7x + 12 = 5 => subtract 5 from both sides
-7x + 12 -5 = 0 =>
-7x + 7 = 0
x = 1
2. 4z + 5 = -3z - 8 => add 3z to both sides
4z + 3z + 5 = -8 => subtract 5 from both sides
7z = -8 -5 = -13 => divide both sides by 7
z = -13/7
Thank you,
MrB
