A 2.0-kilogram cart is initially at rest on a level floor. Determine the kinetic energy of the cart after a constant horizontal 8.0-newton force is applied to the cart over a distance of 1.5 meters.

Question

contestada

Respuesta :

skyluke89 skyluke89 · Answer 1 · 2019-02-17T03:56:23+01:00

Answer:

12 J

Explanation:

For the work-energy theorem, the work done on the cart is equal to the kinetic energy gained by the cart:

[tex]W=K_f - K_i[/tex]

where

W is the work done

Kf is the final kinetic energy

Ki is the initial kinetic energy

The work done is equal to the force times the displacement:

[tex]W=Fd=(8.0 N)(1.5 m)=12 J[/tex]

The initial kinetic energy of the cart is zero, since the cart is at rest:

[tex]K_i=0[/tex]

So, we can re-arrange the equation above to calculate the final kinetic energy of the cart:

[tex]K_f = K_i + W=0+12 J=12 J[/tex]

okpalawalter8 okpalawalter8 · Answer 2 · 2022-04-07T10:35:00+02:00

The kinetic energy of the cart is mathematically given as

Kf=12 J

Question Parameter(s):

A 2.0-kilogram cart is initially at rest on a level floor

a constant horizontal 8.0-newton force is applied

Generally, the equation for the work is mathematically given as

W=K_f - K_i

Therefore

W=Fd

W=(8.0 N)(1.5 m)

W=12 J

In conclusion,

Kf = K_i + W

Kf=0+12 J

Kf=12 J