If an object is projected upward with an initial velocity of 129129 ft per sec, its height h after t seconds is h equals negative 16 t squared plus 129 th=−16t2+129t. Find the height of the object after 44 seconds.

We have been given that an object is projected upward with an initial velocity of 129 ft per sec, its height h after t seconds is [tex]h(t)=-16t^2+129t[/tex].

To find the height of object after 4 seconds, we will substitute t=4 in our given function.

[tex]h(4)=-16*4^2+129*4[/tex]

[tex]h(4)=-256+516[/tex]

[tex]h(4)=260[/tex]

Therefore, the height of the object after 4 seconds will be 260 feet.

If an object is projected upward with an initial velocity of 129129 ft per​ sec, its height h after t seconds is h equals negative 16 t squared plus 129 th=−16t2+129t. Find the height of the object after 44 seconds.

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If an object is projected upward with an initial velocity of 129129 ft per sec, its height h after t seconds is h equals negative 16 t squared plus 129 th=−16t2+129t. Find the height of the object after 44 seconds.