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ShyzaSling

Answer

1m/s

Explanation

Given that:

Mass of first blob = 2kg = m1

Velocity of blob = 4m/s = v1

Mass of second blob = 6kg = m2

Velocity of blob = 0m/s = v2

To find:

Final velocity = Vf

This question is of inelastic collision which is any collision between objects in which some energy is lost.

Formula to be use:

(m1*v1) + (m2*V2) = Vf(m1 + m2)

(2*4) + (6*0) = Vf(2+6)

8 + 0 = Vf(8)

8 = Vf(8)

Vf = 1 m/s

So the speed of two blobs immediately after colliding = 1 m/s

shubhamchouhanvrVT

The speed of the to stick together blobs immediately after colliding will be    [tex]V_f=1\frac{m}{s}[/tex]

What will be the speed of the to stick together blobs immediately after colliding?

It is given in the question

Mass of first blob  [tex]m_1[/tex]= 2kg  

Velocity of blob   [tex]V_1[/tex]= 4m/s  

Mass of second blob [tex]m_2[/tex] = 6kg  

Velocity of blob [tex]V_2[/tex]= 0m/s  

For finding the speed of the to stick together blobs immediately after colliding   [tex]V_f[/tex]

Since the collision of the putty is inelastic so from the conservation of energy

[tex](m_1 V_1)+(m_2 V_2)=V_f(m_1+m_2)[/tex]

[tex](2\times4)+(6\times0)=V_f(2+6)[/tex]

[tex]0+8=V_f(8)[/tex]  

[tex]V_f=1 \frac{m}{s}[/tex]

Thus the speed of the to stick together blobs immediately after colliding will be    [tex]V_f=1\frac{m}{s}[/tex]

To know more about inelastic collision follow

https://brainly.com/question/7694106

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