Answer:
The two consecutive whole numbers are [tex]11[/tex] and [tex]12[/tex]
Step-by-step explanation:
Let
[tex]x=\sqrt{122}[/tex]
so
squared both members
[tex]x^{2} =122[/tex]
we know that
[tex]11^{2} =121[/tex]
[tex]12^{2} =144[/tex]
therefore
[tex]x^{2} =122[/tex]
The value of x lie between [tex]11[/tex] and [tex]12[/tex]
The two consecutive whole numbers are [tex]11[/tex] and [tex]12[/tex]
