Answer:
Step-by-step explanation:
Let s be the speed of the boat in the still water,
and let c be the speed of the current. Then,
(s-c) is the effective speed upstream and (s+c) is the effective speed downstream.
Now, using the formula,
distance=time×speed, we get
14(s-c)=336 (1)
12(s+c)=336 (2)
Divide the equation (1) by 14, and the equation (2) by 12,
s - c = 24
s + c = 28
Adding both the equations, we get
⇒2s=52
⇒s=26mph in still water.
Puts=26 in equation (1), we get
14(26-c)=336
26-c=24
c=2 mph current.
