Answer:
Perimeter of the triangle=24 units
Step-by-step explanation:
The given vertices of the triangle ABC are A(1,1), B(7,1) and C(1,9).In order to fin the perimeter, we need to find the lengths of the triangle.
Thus, AB=[tex]\sqrt{(7-1)^{2}+(1-1)^{2}}=\sqrt{36}=6[/tex],
BC=[tex]\sqrt{(1-7)^{2}+(9-1)^{2}}=\sqrt{36+64}=\sqrt{100}=10[/tex] and
AC=[tex]\sqrt{(1-1)^{2}+(9-1)^{2}}=\sqrt{64}=8[/tex]
Now, Perimeter of the triangle= Sum of all the sides
=AB+BC+AC
=6+10+8
=24 units.
Thus, Perimeter of the triangle=24 units
