Let the height of the person with shoulder width of 18.5 be = x
As given, A person who is 64 inches tall has a shoulder width of 16 inches.
So, we have to find the height when the shoulder width is 18.5 inches.
We can relate these two by ;
[tex]\frac{64}{16}=\frac{x}{18.5}[/tex]
[tex]16x=64*18.5[/tex]
[tex]16x=1184[/tex]
[tex]x=74[/tex]
Hence, the height of the person should be 74 inches.
Answer:
Part a) [tex]\frac{h}{w}=\frac{4}{1}[/tex]
Part b) [tex]h=74\ in[/tex]
Step-by-step explanation:
Let
h-----> the height of the person
y----> the width of the shoulder of the person
we know that
[tex]\frac{h}{w}=\frac{64}{16}=\frac{4}{1}[/tex]
For [tex]w=18.5\ in[/tex]
Find the value of h
[tex]\frac{h}{18.5}=\frac{4}{1}[/tex]
[tex]h=18.5*4=74\ in[/tex]
