Answer:
The length of third sides of the triangle is 2.65 units.
Step-by-step explanation:
It is given that triangle had two sides of length 2 and 3 and that the angle between there two sides is 60.
a = 2 units, b = 3 units and angle C = 60°.
Law of Cosine:
[tex]c^2=a^2+b^2-2ab\cos C[/tex]
[tex]c^2=2^2+3^2-2(2)(3)\cos (60^{\circ})[/tex]
[tex]c^2=4+9-12(\frac{1}{2})[/tex]
[tex]c^2=7[/tex]
Square root both sides.
[tex]c=2.64575131106\approx 2.65[/tex]
Therefore the length of third sides of the triangle is 2.65 units.
