Answer:
Step-by-step explanation:
Since, AB is the vertical pole, then the guy wires AC and AD will be inclined at equal angles to keep the pole stand vertical. therefore, ∠CAB=∠BAD.
From ΔABD, we have
∠ABD+∠BAD+∠ADB=180° (Angle sum property)
⇒62°+∠BAD+90°=180°
⇒∠BAD=180-152
⇒∠BAD=28°
Thus, using trigonometry in ΔABD,
[tex]\frac{AD}{AB}=sin62^{\circ}[/tex]
⇒[tex]\frac{AD}{300}=0.882[/tex]
⇒[tex]AD=264.88 inches[/tex]
Now, ∠CAB=∠BAD=28°
From ΔCAB, we have
[tex]\frac{AB}{AC}=cos28^{\circ}[/tex]
⇒[tex]\frac{300}{AC}=0.882[/tex]
⇒[tex]AC=340.13 inches.[/tex]
