Respuesta :
Answer:
The function g(x) is defined as [tex]g(x)=-\frac{1}{6}(0.2)^{x-9}[/tex].
Step-by-step explanation:
The given function is
[tex]f(x)=-(0.2)^x[/tex]
The function f(x) transformed 9 units right, compressed vertically by factor of 1/6 and reflected across the x-axis.
The transformation of function is defined as
[tex]g(x)=kf(x+b)+c[/tex]
Where, k is vertical stretch, b is horizontal shift and c is vertical shift.
If b>0, then the graph of f(x) shifts b units left and if b>0, then the graph of f(x) shifts b units right.
If c>0, then the graph of f(x) shifts c units upward and if c>0, then the graph of f(x) shifts c units downward.
The value of b is -9 because the graph shifts 9 units right. The value of k is 1/6. If the graph of function f(x)reflect across x-axis, therefore the function is defined as -f(x).
[tex]g(x)=\frac{1}{6}(-f(x-9))[/tex]
[tex]g(x)=-\frac{1}{6}(0.2)^{x-9}[/tex] [tex][\because f(x)=-(0.2)^x][/tex]
Therefore the function g(x) is defined as [tex]g(x)=-\frac{1}{6}(0.2)^{x-9}[/tex].
Answer:
g(x) = -⅙(0.2)^(x – 9)
Step-by-step explanation:
F(x) = 0.2^x
(a) Transformation to the right
You transform a function 9 units to the right by subtracting 9 from the value of x. Thus, the function becomes
F₁(x) = 0.2^(x – 9)
(b) Vertical compression
To compress a function vertically by a factor of 6, you divide the whole function by 6. Thus, the function becomes
F₂(x) = ⅙F₁(x) = ⅙(0.2)^(x – 9)
(c) Reflection across x-axis
When you reflect a point (x, y) across the x-axis, the x-coordinate remains the same, but the y-coordinate gets the opposite sign. Thus,
g(x) = -⅙(0.2)^(x – 9)
The image below shows F(x) and its appearance after each of the operations.
